Zc is an altitude, m∠cyw (5x + 22)°, and m∠wzc (12x)°. find m∠wzc
a) 32 °
b) 45 °
c) 48 °
d) 20 °

The  m∠WZC is 48 degrees.

ZC should be the altitude,

So

∠ZCY = 90°

Now  

The sum of the 3 angles in a triangle = 180°

And,  

Sum the 3 angles in ΔCYZ and equate to 180

90 + 5x + 22 + 12x = 18

17x + 112 = 180

17x = 68  

x = 4

Hence

∠WZC = 12x

= 12(4)

= 48°

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C

Step-by-step explanation:

ZC is an altitude, thus ∠ZCY = 90°

The sum of the3 angles in a triangle = 180°

Sum the 3 angles in ΔCYZ and equate to 180

90 + 5x + 22 + 12x = 180 ← simplify left side

17x + 112 = 180 ( subtract f112 from both sides )

17x = 68 ( divide both sides by 17)

x = 4

Hence

∠WZC = 12x = 12 × 4 = 48° → C

the correct answer is x/3+10≥32

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