Consider the expression x^2-b. what has to be true about the values of b for this expression to be factorable?

b must be greater than zero.

Step-by-step explanation:

If "b" is negative then our equation will not have real solutions. The expression x^2-b can be factorable only if b>0, and the factorized form will be: (x+b)(x-b)=0

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value