Given the system of equations, what is the solution? 2x + 3y = 2 3x - 4y = 20

x = 4 and y = -2

Step-by-step explanation:

First equation: 2x + 3y = 2.

Second equation: 3x - 4y = 20.

Using the substitution method:

From Equation 1:

3y = 2 - 2x.

y = (2 - 2x)/3 (Equation 3).

Put equation 3 in equation 2:

3x - 4(2-2x)/3 = 20.

Taking LCM:

(9x - 4(2-2x))/3 = 20.

Cross Multiplying:

9x - 8 + 8x = 60

17x = 68

x = 4.

Put x = 4 in Equation 3:

y = (2 - 2(4))/3

y = (2-8)/3 = -6/3 = -2.

Therefore, x = 4 and y = -2!!!

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