Mark charged a battery. each minute, the percentage of the battery's capacity that was charged increased by 2.52.52, point, 5 percent. after 171717 minutes of charging, the battery was 61.561.561, point, 5 percent full. how full was the battery when the charging began?

19%.

Step-by-step explanation:

We have been given that Mark charged  a battery. Each minute, the percentage of the battery's capacity that was charged increased by 2.5%. After 17 minutes of charging, the battery was 61.5% full.

We will use slope-intercept form of equation to solve our given problem. We know that the equation of a line in slope-intercept form is: , where,

m = Slope of line,

b = The y-intercept or initial value.

Since battery is charged 2.5% per minute, so slope of line would be 2.5.

We are also told that after 17 minutes of charging, the battery was 61.5% full. Now, we will use point to solve for initial value or b as:

Therefore, the battery was 19% full, when the charging began.

sinn is the total amount of students now and m were the students before, you subtract them both (n-m) and divide that by m. then, since to get a percentage from a fraction you have to multiply by 100, your answer should look like this: n-m/m*100

step-by-step explanation:

bdhfnfhjffjkfjfjfjjf