In a sample of 35 high school seniors, 14 of them are attending college in the fall. find the 95% confidence interval for the true proportion of high school seniors that will attend college in the fall from the population.

Between 23.77% and 56.23%

Step-by-step explanation:

On your TI-84

Press STAT

Use right arrow to scroll over to highlight TESTS

Use down arrow to scroll down to A:1-PropZInt...

Press ENTER

Make the screen read

x:14  

n:35

C-Level:0.95

Calculate

highlight  Calculate

Press ENTER

See this:

(.2377,.5623)

p(hat)=.4

n=35

The confidence interval is 0.2377 < p < 0.5623

Between 23.77% and 56.23%

connie < felicia < stew

step-by-step explanation:

stew:

we need to find the slope

m = (y2-y1)/ (x2-x1)

    = (2650-795)/(10-3)

    = 1855/7

265 words per minute

connie:

we need to find the slope

m = (y2-y1)/ (x2-x1)

we have two points (0,0) and (4,800)

m = (800-0)/(4-0)

  m = 800/4

    200 words per minute

felicia:

260 words per minute

200< 260 < 265

connie < felicia < stew

the final price would be 29.6925

step-by-step explanation:

39.59 minus 25% equals 29.6925