Use substitution to solve the system of equations. y=x +1.74 4x-2y =4
(3.75,0) (4,4) (3.75,5.5) (5.5,4)

y = 3.75+1.74= 5.49=5.5 =5.5

4(3.75) - 2(5.5) =15 - 11 =4

Step-by-step explanation:

y = x+ 1.74 →  -x + y = 1.74  

(1/2)(4x - 2y = 4) → 2x - y = 2

Add two eq → x=3.74 and y=5.5

The problem says that u need replace but with the process before you can get the result easily.

y = 3.75+1.74= 5.49=5.5 ≠ 0

4(3.75) - 2(0) =15 ≠ 4

y = 4+1.74= 5.74=6 ≠ 4

4(4) - 2(4) =8 ≠ 4

y = 3.75+1.74= 5.49=5.5 =5.5

4(3.75) - 2(5.5) =15 - 11 =4

y = 5.5+1.74= 7.24 ≠ 0

4(5.5) - 2(4) =14 ≠ 4

step-by-step explanation:

equation

you are asked to write the equation

  expression = 0

using the given expression. when you do that, you have

  2x^2-2x-12 = 0

factoring

you can see that each of the coefficients is even, so a factor of 2 can be removed immediately.

  2(x^2 -x -6) = 0

if you multiply the binomials (x+a)(x+b), you get

  (x +a)(x +b) = x^2 +(a+b)x +ab

this tells you the coefficient of x is the sum of two factors of the constant term. here, that means -1 is the sum of two factors of -6. we want to know those factors so we can factor the trinomial.

  -6 = -1×6 = -2×3 = -3×2 = -6×1

the factor pair that sums to -1 is {-3, 2}, so our factorization is

  2(x -3)(x +2) = 0

solutions

the solutions to this equation are the values of x that make the product zero. a product is zero only when only of the factors of the product is zero. here, that means

  x - 3 = 0

  x = 3 . . . add 3 to both sides of the equation

or

  x +2 = 0

  x = -2 . . . add -2 to both sides of the equation

the solutions to the equation are x=3 or x=-2. both of these values of x satisfy the equation—they make it be true.