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Mathematics, 30.07.2019 21:20 serenityarts123

Solve sin2∅=sin∅ on the interval 0≤x< 2\pi .
a. 0,\frac{\pi }{3}
b. 0, \pi, \frac{\pi }{3}, \frac{5\pi }{3}
c. 0, \pi, \frac{2\pi }{3},\frac{4\pi }{3}
d. \frac{3\pi }{2}, \frac{\pi }{2},\frac{\pi }{6}, \frac{5\pi }{6}

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You know the right answer?
Solve sin2∅=sin∅ on the interval 0≤x< 2[tex]\pi[/tex] .
a. 0,[tex]\frac{\pi }{3}[/tex]
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