1. consider the equation ax^2+bx+c=0, where a, b and c are odd integers. prove that if z is a solution to the given equation, then z must be an irrational number. you may assume that sum of two odd integers is even product of two odd integers is odd sum of two even integers is even product of two even integers is even sum of an odd and an even integer is odd product of an odd and an even integer is even

Step-by-step explanation:

Given that

Where a,b,and c are odd integers.

We know that solution of quadratic equation given by following formula

Now we have to prove that above solution is a irrational number when a,b and c all are odd numbers.

Let's take a=3  ,b=9 ,c= -3   these are all odd numbers.

Now put the values

So

We know that square roots,cube roots etc are irrational number .So we can say that above value z is also a irrational number.

When we will put any values of a,b and c (they must be odd integers) oue solution will be always irrational.

alright well the answers to your question is

2xy/9 hope this have a nice day : )

step-by-step explanation:

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.