Find the number of subsets of the set. (mom, dad, son, daughter) a) 14 b) 12 c) 8 d) 16 let u = {q, r, s, t, u, v, w, x, y, a}: a = {q, s, u, w, y}: b = {q, s, y, x}: and c = {v, w, x, y, z}. list the members of the indicated set, using set braces. (a union b)' a) {r, t, v, x} b) {s, u, w} c) {t, v, x} d) {r, s, t, u, v, w, x, z}c union a' a) {q, s, u, v, w, x, y, z} b) {q, r, s, t, u, v, x, z} c) {w, y} d) {s, t}

Option D:16

={r,t,v,z}

={r,t,v,w,x,y,z}

Step-by-step explanation:

We are given a set {Mom,dad,Son, daughter}

1.We have to find the number of subsets of given set

To find the number of subsets  using formula where n= Number of elements in a set

Therefore, we have 4 elements

Therefore, total number of subsets of a given set =

Hence, option D is true.

16.Let U={q,r,s,t,u,v,w,x,y,z}

A={q,s,u,w,y}

B={q,s,y,x}

C={v,w,x,y,z}

={q,s,u,w,x,y}

Therefore, ={q,r,s,t,u,v,w,x,y,z}-{q,s,u,w,x,y}={r,t,v,z}

U- A={r,t,v,x,z}

={v,w,x,y,z} {r,t,v,x,z}={r,t,v,w,x,y,z}

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

linear pair postulates