Identify the quadratic function(s). (select all that apply.)
8-5x = 4(3x - 1)
(48 + 272a-1)+1=0.
1 2y + 2/3y - 5) = 0
2bb-7)+b=0

For this case we have that by definition, a quadratic function is given by:

We evaluate the given equations:

Option A:

It is a linear equation!

Option B:

It is a linear equation!

Option C:

It is a linear equation!

Option D:

It is a quadratic equation!

Option D

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15