Randall opened a savings account on june 1st and made the following deposits: $212.19, june 5th $29.03, june 12 $307.15, june 19th $652.00 and june 30, $78.75. assuming he made no withdrawals, approximately how much did he have in the savings account at the end of the month of june?

The amount of money he have in the savings account at the end of the month of June is:

                           $ 1279.12

It is given that:

Randall opened a savings account on June 1st and made the following deposits:

June 1st        $212.19

June 5th       $29.03

June 12th      $307.15

June 19th      $652.00

and June 30  $78.75.

Also, he made no withdrawals this means that the amount of money in the end month of June will be equal to the sum of all the money that was deposited in the account in different days of June.

Hence, the amount of money in the account will be:

212.19+29.03+307.15+652+78.75

= $ 1279.12

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

a

step-by-step explanation: