Plz what is f[g(3)] for the following functions? f(x) = 4x2 − 3 g(x) = 5x − 2
a. f[g(3)]=13
b. f[g(3)]=163
c. f[g(3)]=363
d. f[g(3)]=673
plz answer asap

D. 673 if the functions are f(x)=4x^2-3 and g(x)=5x-2

Step-by-step explanation:

f(g(3)) is what we need to find.

We start with the inside first: g(3).

g(3) means to take the expression labeled g and replace the input, the x, with 3:

5(3)-2

15-2

13

So g(3) is 13.

Let's go back to finding f(g(3)):

f(g(3))

f(13)   :I replaced g(3) with 13.

f(13) means to use the expression labeled f and plug in 13 for the input, x:

4(13)^2-3

4(169)-3

676  -3

673

So f(13) is 673.

Let's go back to the problem one more time:

f(g(3))=f(13)=673.

D

Step-by-step explanation:

Assuming

and

We first evaluate g(x) at x=3. We get 15-2=13

Now you plug in x=13 for f(x)

you get:

Which equals 673

d

step-by-step explanation:

given

y + 3 = - 4(x - 2) ← distribute the parenthesis

y + 3 = - 4x + 8 ( subtract 3 from both sides )

y = - 4x + 5 → d

30.5*10=350$

you have to multiply the number without the decimal point then add it later but if its tenn u must move the place value of the decimal point 1 to the right.