What is the mean absolute deviation for 7,5,1,6,2 and 3

mean absolute deviation = 2

Step-by-step explanation:

Mean absolute deviation, M.A.D is given by

M.A.D= 1/n ∑ |Xi-X|

where i= 1 to n

X= mean of values

Xi= ith value

n=total number of values

Now\given values are 7,5,1,6,2 and 3

Mean= 7+5+6+1+2+3/6

  X= 4

Now

M.A.D= 1/6{(|7-4|+|5-4|+|1-4| +|6-4|+|2-4| +|3-4|}

        = 1/6 (12)

         =2 !

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.