what are the zero(s) of the function f(x) = 4x^2-36x/ x-9
a) x= -9
b) x= 0
c) x=9
d) x= 0 and x=9

We have a function f(x) defined below:

f(x) = (4x²-36x)/(x-9)

We can factor the top:

f(x) = (4x)(x-9)/(x-9)

We see an (x-9) term in the top and bottom. This means that we can reduce f(x) down to:

f(x) = 4x

But we must keep in mind that due to the canceling (x-9) terms, there is a removable discontinuity (hole) at x = 9

To find the zeros of f(x), simple set f(x) = 0 and solve for x:

f(x) = 4x

0 = 4x

x = 0

Choice B

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step-by-step explanation:

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