Two points a and b lie on a line given by the equation y=3x+2. point a lies on the y-axis and point
b lies four units to the left of the y-axis. the line segment ab is dilated about the origin by a scale of factor
of to obtain the line segment a'b', what are the coordinates of a'and b’?
(a) a'(0, 1) and b'(-4,-5)
(b) a'(0,4) and ,-20)
(c) a'(0, 1) and b'(-2,-5)
d) a'(0,4) and b'(-8, -20)

h

step-by-step explanation:

imma say 16%. sorry if its wrong. i'm doing the same stuff right now

step-by-step explanation:

b

step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (3, - 5) ← 2 points on the line

m = = = - 3

with m = - 3 and (a, b) = (3, - 5), then

y - (- 5) = - 3(x - 3), that is

y + 5 = - 3(x - 3) → b