Two objects are moving along separate linear paths where each path is described by position, d and time, t. the variable d is measured in meters and the variable t is measured in seconds. the equation describing the graph of the position of the first object with respect to time is d=2.5t+2.2. the graph of the position of the second object is a parallel line passing through (t=0,d=0). what is the equation of the second graph?

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

this answer is !

what’s the question?

step-by-step explanation:

*calories burned = (weight)(calorie factor)*

calories burned = 180 (0.65)

calories burned = 117

the calories he used up is 117, which is 65% of his weight.