The time spent waiting in the line is approximately normally distributed. the mean waiting time is 6 minutes and the standard deviation of the waiting time is 2 minutes. find the probability that a person will wait for more than 4 minutes.

0.034

Step-by-step explanation:

Data:

Let the standard deviation be :

The mean be:

Therefore, P (x>4) which is  the probability that a person will wait for more than 4 minutes is given by:

 =

Therefore,

P(x > 4)  = P (z > -1)

             = P (z < -1)

From the z-tables, we find 0.034

i believe the answer is 68cm

step-by-step explanation:

i just took 34 x 2 because the space between v and y is the same as y to k.

a

b

d

step-by-step explanation: