What are the zeros of f(x) = x2 - 12x + 36?
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a. x= -6 and x = 6
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b. x=-6 only
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c. x= 6 only
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d. x= -4 and x = 9

c. x = 6 only

Step-by-step explanation:

In order to calculate the zeros of f(x), we need to set it equal to zero and find the corresponding values of x.

Using the midterm breaking, we can split -12x into two such terms whose sum will be -12x and product will be 36x². These two terms are -6x and -6x

So, the above expression can be written as:

This means, the zero of f(x) occurs at x = 6 only.

where are the images of the functions i can only see the question you typed.

step-by-step explanation:

answer: 7. if the functions had a negative leading coefficient and is of even degree, which statement about the graph is true?

step-by-step explanation: