Given the arithmetic sequence a1,a2,a3,a4 45, 51, 57, 63 what is the value of a34?

243.

Step-by-step explanation:

The first term is 45 and the common difference is 6.

The nth term is a1 + (n - 1)d   where a1 = the first term and d = the common difference, so

the 34th term A34 = 45 + (34 - 1)6

= 45 + 198

= 243.

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

452,489 to the nearest thousand is 452,000