At what point is the maximum value found in the system of inequalities graphed below for the function f(x, y) = 4x ­- 3y?
a(5, 0)
b(4, 6)
c(7, 5)
d(8, 2)

D.

Step-by-step explanation:

Just see which point yields the highest value.

f(x,y)=4x-3y

Checking choice A:

(x,y)=(5,0)

f(5,0)=4(5)-3(0)=20-0=20.

Checking choice B:

(x,y)=(4,6)

f(4,6)=4(4)-3(6)=16-18=-2.

Checking choice C:

(x,y)=(7,5)

f(7,5)=4(7)-3(5)=28-15=13.

Checking choice D:

(x,y)=(8,2)

f(8,2)=4(8)-3(2)=32-6=26

Choice D yields the highest value of the points given for our relation f(x,y)=4x-3y.

n

step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204