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a scientist rolls two balls a and b down two different ramps. ball a rolls 4 meters in the 1st second, 9 meters in the 2nd second, 14
meters in the 3rd second, and so on. ball b rolls 3.5 meters in the 1st second, 6.5 meters in the 2nd second, 9.5 meters in the 3rd
second, and so on. how many meters would each ball roll in 10 seconds?
select one
a. a: 49 m: b: 305 m
b. a: 54 m; b: 33.5 m
ca: 59 m: b: 36.5 m
d. a: 85 m: b: 72 m

Option A. A: 49 m: B: 30.5 m

Step-by-step explanation:

Ball A rolls 4 meters in the 1st second, 9 meters in the 2nd second, 14 meters in the 3rd second, and so on.

We can see that after each second the total distance traveled by ball increases by 5 meters.

So, we can solve this as an arithmetic sequence that is

For ball A, a = 4 n = 10 d = 5

Ball B rolls 3.5 meters in the 1st second, 6.5 meters in the 2nd second, 9.5 meters in the 3rd  second, and so on.

For ball B, a = 3.5 n = 10 d = 3

For ball A:

After 10 seconds, the distance will be

= = 49 meters

For ball B:

After 10 seconds, distance covered will be

= = 30.5 meters.

Hence, the answer is option A.

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

c

step-by-step explanation: