Use the diagram to find the measure of the given angle.
given angle: prq

∠PRQ = 85°

Step-by-step explanation:

∠PRS and ∠TRQ are vertical angles and congruent, thus

4x + 15 = 3x + 35 ( subtract 3x from both sides )

x + 15 = 35 ( subtract 15 from both sides )

x = 20

Hence ∠PRS = (3 × 20) + 35 = 60 + 35 = 95°

∠PRQ and ∠PRS form a straight angle and are supplementary, hence

∠PRQ = 180° - 95° = 85°

Angle QRP = 85

Step-by-step explanation:

Hopefully you can see QRS and TRP both equal 180 degrees, we will use this.  

QRS is the same as QRP and PRS added together.  Just like TRP is TRQ and QRP.  We will call QRP R for simplicities sake, and we are given a formula for PRS and TRQ.  PRS = 3x+35 and TRQ = 4x+15.

So now we have two equations.

180 = QRP + PRS = R + 3x + 35

180 = TRQ + QRP = 4x + 15 + R

So it's basically a system of equations.

180 = 35 + R + 3x

145 = R + 3x

R = 145 - 3x

180 = 4x + 15 + R

Replace R with what we found in the last  equation

180 = 4x + 15 + 145 - 3x

180 = x +160

x = 20

Now go back to the first equation and plug 20 in for x

R = 145 - 3x

R = 145 -3(20)

R = 145 - 60

R = 85

So Angle QRP = 85

Let em know if something doesn't make sense.  

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v