Suppose you just received a shipment of eleven televisions. three of the televisions are defective. if two televisions are randomly selected, compute the probability that both televisions work. what is the probability at least one of the two televisions does not work?

 The probability that both televisions work : 0.5329

The  probability at least one of the two televisions does not work : 0.4671

Step-by-step explanation:

Given : The total number of television : 11

The number of defective television : 3

The probability that the television is defective :

Binomial distribution formula :-

, where P(X) is the probability of getting success in x trials, p is the probability of success and n is the total trials.

If two televisions are randomly selected, then the probability that both televisions work:

The probability at least one of the two televisions does not work :

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol

6. 104

7. 52/37

8. 2704

9. 140608

10. -52

11. |52|=52

12. 1/52

13. 156

14. 26

15. 40

16. 37

17. -364

18. 53 1/3

19. 50.96

20. 43 2/3

21. 78

22. 50.75

23. 47.63

24. 163.28

25. 10400

26. 338

27. 208

28. 2704 square inches

29. 312 square meters

30. don't know what its asking, tell me so i can tell you

31. 8490.56

32. 52 degrees would be an acute angle

33. 128 degrees

34. 20.8

35. 39

36. 208