In this problem, you will show that every polynomial parametric curve in the plane r2 satisfies a polynomial cartesian equation. let x = p(t) and y = q(t) where p, q ∈ p(r) are fixed polynomials. note that each expression x iy j is a polynomial p(t) i q(t) j in the variable t. (a) find a function l: z≥0 × z≥0 → z≥0 (i. e. a function that takes in a pair of nonnegative integers (m, n) and returns a nonnegative integer l(m, n)) so that if 0 ≤ i ≤ m and 0 ≤ j ≤ n, then x iy j = p(t) i q(t) j ∈ pl(m, n) (r). of course your choice of l will need to depend on p and q somehow, but that is fine because they are fixed throughout this problem. (b) choose m and n judiciously so th

answer: i would say b

step-by-step explanation:

with the way the question is worded, i believe b is the answer

the cost of the apple depends on the weight

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3