How many solutions does the equation x_1 +x_2+x_3+x_4+x_5=21 have where x_1, x_2, x_3, x_4, and x_5 are nonnegative integers and x_1 > = 1?

Step-by-step explanation:

    (given)

Let us consider :

=

=

=

 =

=

Now, by substituting the above considerations in the above equation, we get:

where,

1

then it follows

n = 20

r = 4

then no. of solutions for the eqn =

                                                      =

                                                      = 10626

Answer :

no. of solutions for the eqn 10626

step-by-step explanation:

1 1/5

step-by-step explanation: