Find the point closest to the origin in the line of intersection of the planes y + 2z = 10 and x + y = 11. the point closest to the origin is . (type an ordered triple.)

Answer with explanation:

The equation of two planes are

  1.→y +2 z=10

   2.→x+y=11

To find the point of Intersection of two planes

let,→ y=t

→2 z=10 - t

10 -2 z=t

→x=11 -t

11 -x=t

So,Writing equation of line which is intersection of two planes

    → 11 -x = y= 10-2 z=t

                                          ---------------------------------(1)

⇒Putting , x=0, y=0 and z=0 in the above equation ,to find the point Closest to Origin which will be

    =(11, 0, 10)

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

5

step-by-step explanation: