Assume that hybridization experiments are conducted with peas having the property that for offspring, there is a 0.75probability that a pea has green pods. assume that the offspring peas are randomly selected in groups of 10.complete parts (a) through (c) below. a. find the mean and the standard deviation for the numbers of peas with green pods in the groups of 10.the value of the mean is muequalsnothingpeas.

The value of the mean and standard deviation values of the hybridization experiment is :

Given the Parameters :

To obtain the mean , we use the relation :

Mean, μ = np

Mean, μ = (10 × 0.75) = 7.5

To obtain the Standard deviation, we use the relation :

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The mean is and standard deviation is .

Step-by-step explanation:

The mean and standard deviation for the binomial distribution is given by :-

,where n is the number of trials and p is the probability of getting success in each trial.

Given : The probability that a pea has green pods :

Then , the standard deviation for the numbers of peas with green pods in the groups of 10  :-

Hence, the mean is and standard deviation is  .

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .

step-by-step explanation:

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