Mathematics, 19.07.2019 18:10 alee885
How many solutions are there to the equation x1 +x2 +x3 +x4 +x5 = 18, where x1, x2, x3, x4, x5 are non-negative integers, given the follow restrictions: four of the variables must be odd, and the remaining variable (which may be odd or even) yield a remainder of 2 when divided by 3? justify your answer.
Answers: 3
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Mathematics, 21.06.2019 16:30
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How many solutions are there to the equation x1 +x2 +x3 +x4 +x5 = 18, where x1, x2, x3, x4, x5 are n...
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