Aman is four times as older as his son. in four years time he will be three times as old. what are their ages now?

The son is 8 years old

The father is 32 years old

Step-by-step explanation:

Let the man age be x

Let the son age = y

Right now the man is four times as older as his son = x=4y

In four years time he will be three times as old. ⇒x+4 =3(y+4)

Now substitute the value x=4y in x+4=3(y+4)

x+4=3(y+4)

4y+4=3(y+4)

4y+4=3y+12

Combine the like terms:

4y-3y =12-4

y=8

If the son is 8 years old than;

x=4y

x=4(8)

x=32

Father will be 32 years old

Present age of son: 8 years.

Present age of father: 32 years.

Step-by-step explanation:

Let x represent present age of the son and y represent present age of father.

We have been given that a man is four times as older as his son. 4 times of age of son would be .

We can represent this information in an equation as:

We are also told that in four years time he will be three times as old.

Age of father in 4 years would be .

We can represent this information in an equation as:

Upon substituting in 2nd equation, we will get:

Therefore, the present age of son is 8 years.

Upon substituting in equation , we will get:

Therefore, the present age of father is 32 years.

answer: -8.2562234e+13

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3