At the city museum, child admission is $5.20 and adult admission $9.70. on tuesday, 135 tickets were sold for a total sales of $940.50. how many child tickets were sold that day?

82 children tickets

Step-by-step explanation:

Let the number of adults be x

the number of children be y

hence

total number of admission = 135

hence x+y=135

x=135-y (I)

Also

cost of one adult ticket = 9.7 and that of one child ticket = 5.2

Hence total cost =

9.7x+5.2y=940.5 (II)

substituting x=135-y from (I) in (II)

9.7(135-y)+5.2y=940.5

1309.50 - 9.7y + 5.2y=940.50

1309.50-940.50=9.7y-5.2y

369=4.5y

y=82

Hence x = 135-82

x=53

Hence there were 53 adults and 82 children

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2