Use the method of lagrange multipliers to end the maximum and minimum values of the function subject to the given constraints: f(x, y, z) = yz + xy xy = 1 y^2 + z^2 = 1

Looks like you're looking for the extrema of subject to and . The Lagrangian is

Look for any critical points:

(we don't want )

but then so we omit this case.

Now,

The first two critical points give a minimum value of , and the other two give a maximum value of .

  q

step-by-step explanation:

each line from a vertex to the midpoint of the opposite side is called a median. the point where the medians intersect, point q, is the centroid.

the centroid of δabc is point q.