Use laplace transforms to solve the initial value problem, then give the value of
x'' + 4x = 0; x(0) = 5, x'(0) = 0

x = 5 cos 2t

Step-by-step explanation:

given equation

x'' + 4x = 0 ;     x(0) = 5,       x'(0) = 0

L{ x'' + 4 x } = 0

L{x''} + 4 L{x} = 0

s² . L(x) - s . x(0) - x'(0) + 4 L{x} = 0

( s² + 4 ).  L(x) - 5 s = 0

L(x) =

 = cos at

so,

x = 5  

x = 5 cos 2t

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.

20 feet per second

hope i

-lavira : )