Two marbles are drawn without replacement from a box with 3 white, 2 green, 2 red, and 1 blue marble.
find the probability. both marbles are white

Step-by-step explanation:

Given a box contains 3 White ,2 green,2 red & 1 Blue marble

We have to draw two marbles without replacement

therefore for first draw we have 3 white marble to choose among 8 marbles

i.e.

 choices among the total of options

For second draw we 2 white marbles left therefore no of ways in which a white marble can be choosen is

Therefore required probability is =

P=

P=

do you mean add both of the equations together

because if you do the answer is 10x-5

step-by-step explanation:

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!