Solve 5y'' + 3y' – 2y = 0, y(0) = 0, y'(o) = 2.8 y(t) =( preview

Step-by-step explanation:

The given equation 5y'' + 3y' - 2y =0 can be written as

Solving for complementary function we have Roots of as follows

Thus the complementary function becomes

y=

where

are calculated roots

thus solution becomes

Now to solve for the coefficients we use the given boundary conditions

hence the solution becomes

ƒ = 0.03b

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step-by-step explanation: