Mathematics, 18.07.2019 05:20 trillralyn4060
Find the last two digits of the number 9^9 (hint: 9^9 = 9 (mod 10); hence, 9^9 = 9^9+10k, notice that 9^9 = 89 (mod 100).]
Answers: 3
Mathematics, 21.06.2019 19:50
Prove (a) cosh2(x) − sinh2(x) = 1 and (b) 1 − tanh 2(x) = sech 2(x). solution (a) cosh2(x) − sinh2(x) = ex + e−x 2 2 − 2 = e2x + 2 + e−2x 4 − = 4 = . (b) we start with the identity proved in part (a): cosh2(x) − sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 − sinh2(x) cosh2(x) = 1 or 1 − tanh 2(x) = .
Answers: 3
Mathematics, 21.06.2019 23:30
What is the arc length of the subtending arc for an angle of 72 degrees on a circle of radius 4? o a. 8a oc. 16 t d. 8
Answers: 3
Find the last two digits of the number 9^9 (hint: 9^9 = 9 (mod 10); hence, 9^9 = 9^9+10k, notice t...
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