At 2: 00 pm a car's speedometer reads 30 mi/h. at 2: 20 pm it reads 50 mi/h. show that at some time between 2: 00 and 2: 20 the acceleration is exactly 60 mi/h2.let v(t) be the velocity of the car t hours after 2: 00 pm. then v(1/3) − v(0)/1/3 − 0 = . by the mean value theorem, there is a number c such that 0 < c < with v'(c) = . since v'(t) is the acceleration at time t, the acceleration c hours after 2: 00 pm is exactly 60 mi/h2.

i would say the third one.

step-by-step explanation: liner would mean in a line and the only one that doesn't look like it's even thinking about forming a line would be the third one

side side side

side angle angle

angle side angle

side angle side

step-by-step explanation:

answer: if you weigh 60 pounds on earth, on the moon you will weigh about 10 pounds. if you weigh 120 pounds on earth, you will weigh about 20 pounds on the moon. since weight is caused by the mass of two objects that are near each other, the bigger the objects, the more the force of gravity.

step-by-step explanation: if you weigh 60 pounds on earth, on the moon you will weigh about 10 pounds. if you weigh 120 pounds on earth, you will weigh about 20 pounds on the moon. since weight is caused by the mass of two objects that are near each other, the bigger the objects, the more the force of gravity.