Acompany produces two types of solar panels per year: x thousand of type a and y thousand of type b. the revenue and cost equations, in millions of dollars, for the year are given as follows.
r(x, y) = 6x + 8y
c(x, y) =x^2 − 3xy + 8y^2 + 14x − 50y − 4
determine how many of each type of solar panel should be produced per year to maximize profit. the company will achieve a maximum profit by selling nothing solar panels of type a and selling nothing solar panels of type b.

x=2, y=4.

2 thousand of A panels and 4 of B.

Step-by-step explanation:

First, the profit is determined by the revenue minus the cost, so built a profit equation with that information.

Then, use the partial derivative criteria to determine which is the maximum.

The partial derivative criteria says that in the local maximum or minimum, the partial derivatives are equal to zero, so:

So, let's solve the equation system:

First, isolate x:

Eq. 1

Eq. 2

Multiply equation 1 by (-3) and equation 2 by 2:

Sum the equations:

Find x with eq. 1 or 2:

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.

you can't solve x because it is 2 linear equation and you only have one equation