Find the center and radius of the circle whose equation is x^2 + y^2 - 6x - 2y + 4 = 0

center(3,1) radius square root of 6

Step-by-step explanation:

(x^2-6x+9)+(y^2-2y+1)=6

(x-3)^2+(y-1)^2=6

what is the original number? you forgot to add it.

“a term can be a signed number, a variable, or a constant multiplied by a + sign or j sign. in , the terms are 5x , 3y and 8. when a term is made up of a constant multiplied by a variable or variables, that constant is called a coefficient.” i hope this you.