What are the zeros of the function below ? check all that apply. f(x)= 5(x+2)/3(x-1)(x+7)

-2 is a zero if your function is

Please correct me if I'm wrong.

Step-by-step explanation:

Assuming you meant

the zeros are what makes the numerator 0 (any zeros of the top that are also zeros of the bottom should be excluded).

Anyways we just need to find when 5(x+2) is 0.

5(x+2)=0

Divide by 5 on both sideS:

x+2=0

Subtract 2 on both sides:

x=-2

And -2 doesn't make the bottom 0.

Checking to see :   3(-2-1)(-2+7)=3(-3)(5)=-9(5)=-45 (not 0).

So F has zero -2.

  y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x             y

0             0

1             -3

3             -9

-2             6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.

f(x) is going down by 4

step-by-step explanation:

(its either that or its going left by 4)