The number n = 100 + 100^2 + 100^3 + + 100^n . find the least possible value of n such that the number n is divisible by 11. need quickly! !

Step-by-step explanation:

very interesting question. The temptation is to say that n should be 11 and that likely is divisible by 11 but it may not be the smallest.

100 + 100^2 = 100 + 10000 = 10100

The pattern of the series goes 101010101 ... 00...

100 / 11 = The remainder is 1/11

10100 / 11 = the remainder is 2/11

1010100 /11 the remainder is 3/11

The pattern suggests that the remainder will be 0 then n = 11

There might be other ways of doing this, but I don't know them.

d (5 x (-20)) * (100 x (0.7))

step-by-step explanation:

5÷1/100 * -.7 *-20

copy dot flip

5*100 * -.7 *-20

rearrange

5*-20   * 100 *-.7

-100   *-70

7000

a

step-by-step explanation:

strong negative correlation