Find the equation of the axis of symmetry and the coordinates of the vertex of the graph of the function y=2x^2+4x-3

Step-by-step explanation:

write this expression : f(x) = a(x-h)²+k

when  the axis of symmetry is the line  : x =h and the vertex A(h,k)

y=2x²+4x-3

y = 2(x²+2x - 3/2)

y=2((x²+2x+1) -1 -3/2)

y = 2((x+1)² - 5/2)

y = 2(x+1)² -5vertex form      x= -1 the axis of symmetry  and A(-1,-5)the vertex

the reason why your question keeps getting deleted because this is not a school related question : )

i will answer your question though.

i never tried church's