It is estimated that one third of the general population has blood type a a sample of six people is selected at random. what is the probability that exactly three of them have blood type a?

0.2195

Step-by-step explanation:

Binomial distribution formula :-

, where P(x) is the probability of x successes in the n independent trials of the experiment and p is the probability of success.

Given : The probability of that the general population has blood type A =

Sample size : n=6

Now, the probability that exactly three of them have blood type A is given by :-

Therefore, the probability that exactly three of them have blood type A = 0.2195

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2