What is the area of rectangle abcd? coordinate plane with rectangle abcd at a 0 comma 2, b 0 comma 4, c 4 comma 4, and d 4 comma 2
a. 4 square units
b. 8 square units
c. 12 square units
d. 16 square units

option d.   16 square units

step-by-step explanation:

points to remember

area of rectangle = length * breadth

it is given that, a rectangle with coordinates,

a(0, 2), b(0, 4), c(4, 4) and d(4, 2)

to find the length and breadth of rectangle

by using distance formula,

ab = √[(0 - 0)² + (4 - 0)²

  = √16 = 4

bc= √[(4 - 0)² + (4 - 4)²

  = √16 = 4

length = breadth   = 4

to find the area of rectangle

area = length * breadth

  = 4 * 4 = 16 square units

the correct answer is option d.   16 square units

i can answer this question sweetie!

step-by-step explanation:

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.