Find the value of x if m arc adc = (4x + 4)° and m angle abc = 150°.

The measure of angle x is 74°

Step-by-step explanation:

we know that

The inscribed angle measures half of the arc that comprises

so

∠ABC=(1/2)[arc ADC]

substitute the given values

150°=(1/2)[4x+4]

300°=[4x+4]

4x=300-4

4x=296

x=74°

answer: 457.14

step-by-step explanation:

205 - 45 = 160

160 / .35 = 457.142857

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3