The given line passes through the points (0, -3) and (2, 3).
what is the equation, in point-slope form of the line that is
parallel to the given line and passes through the point (
-1, -1)?

y - 1 = (1/3)(x + 1)

Step-by-step explanation:

Look carefully at (0, -3) and (2, 3).  As we move from the first to the second, x increases by 2 (from 0 to 2) and y increases by 6 (from -3 to 3).  Therefore, the slope of this line is m  = rise / run, or m = 6/2, or m = 1/3.  Both lines have the same slope, 1/3, because they are parallel.

Now let's apply the point-slope form of the equation of a straight line.  Here the point in question is (-1, 1) and the slope is 1/3.  Therefore, we have:

y - 1 = (1/3)(x + 1)

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation:

sorry can't

step-by-step explanation:

i googled though and something came up but it was in science langueage not common english sooo