Mathematics, 10.07.2019 21:30 jamesjarrell67

Given that h=10, b=5, and r=3.8, find the area of the unshaded region. use 3.14 for π as necessary. all answers are expressed in square units.
a. 70.34
b. 36.93
c. 25
d. 20.34

Given that h=10, b=5, and r=3.8, find the area of the unshaded region. use 3.14 for π as necessary.

Answers: 1

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Answer from: shamiahG

D. 20.34

In this case, we must calculate first the Areas of the Triangle ( $A_{t}$ ), in square units, and the Circle ( $A_{c}$ ), in square units, later we subtract the Area of the former from the Area of the latter to determine the Area of unshaded region ( $A_{u}$ ), in square units. The Area formulas for each figure are, respectively:

Triangle

$A_{t} = \frac{1}{2}\cdot b\cdot h$ (1)

Circle

$A_{c} = \pi\cdot r^{2}$ (2)

Unshaded Area

$A_{u} = A_{c} - A_{t}$ (3)

Where:

- Height of the triangle.

- Base of the triangle.

- Radius of the circle.

If we know that h = 10 , b = 5 and r = 3.8 , then the area of the unshaded region is:

$A_{t} = \frac{1}{2}\cdot (5)\cdot (10)$

$A_{t} = 25$

$A_{c} = \pi\cdot 3.8^{2}$

$A_{c} \approx 45.365$

$A_{u} = 45.365-25$

$A_{u} = 20.365$

The correct answer is D.

Please see this question related to Area problems: link

Answer from: shibble21

The area of the circle is found using the formula Area = PI x r^2

The area of a triangle is found using the formula Area = 1/2 x base x height.

Using the given dimensions:

Area of the circle = 3.14 x 3.8^2 = 45.3416 square units.

The area of the triangle is 1/2 x 5 x 10 = 25 square units.

To find the area of the unshaded part, subtract the area of the shaded triangle from the circle:

Area = 45.3416 - 25 = 20.3416

Round to two decimal places = 20.34

The answer is D. 20.34

Answer from: Quest

what is the question?

step-by-step explanation:

Answer from: Quest

step-by-step explanation:

i found the life tables for the year 2012.

life table of males at age 30. probability of dying between ages x and x+1

total population:

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old.

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497

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