Seven times the first (smaller) of two consecutive odd integers is equal to five times the second (larger) integer. find each integers.

Let the smaller odd integer be: a

then the larger odd integer which is consecutive to a will be: a+2

It is given that:

Seven times the first (smaller) of two consecutive odd integers is equal to five times the second (larger) integer.

This means that:

7 times of a is equal to 5 times of (a+2)

i.e.

( Since, by using the distributive property of multiplication)

i.e.

Hence, the smaller number is:  5

and the larger number is: 7

( Since a+2=5+2=7 )

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step-by-step explanation:

1+2+3+4+5+6+7+8+9+10 = 55

2*10 = 20

55-20 = 35