Find the general solution to y + 17y" + 74y' + 58y = 0 y = c_1e^-t + c_2e^(8 - squareroot 6)t + c_3e^(8 + squareroot 6)t y = c_1e^-t + c_2e^8t + c_3e^-8t y = c_1e^t + c_2e^- squareroot 6t + c_3e^squareroot 6t y = c_1e^-t + c_2e^- squareroot 6t + c_3e^squareroot t y = c_1e^-t + c_2e^(-8 - squareroot 6)t + c_3e^(-8 + squareroot 6)t y = c_1e^t + c_2e^8t + c_3e^-8t

what are ur choices?

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).