Let y = safe load in pounds and x = length in feet of a horizontal beam. a constant of proportionality k exists such that y=k/x if a beam can hold 2,000 pounds at 15 feet, what is the safe load if the length of the beam is 10 feet?
answers: 300 pounds, 3,000 pounds, 20,000 pounds

Safe load of the beam is 3000 pounds.

Step-by-step explanation:

If a horizontal beam of x feet length can hold y pounds safe load, the expression that represents the relation between load and length of the beam is

y =

If y = 2000 pounds and x = 15 feet

then 2000 =

k = 15×2000 = 30000

Now we will calculate the safe load when beam is 10 feet long.

From the formula,

y = pounds

Therefore, safe load of the beam is 3000 pounds.

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