The equation of line qr is x + 2y = 2. what is the equation of a line perpendicular to line qr in slope-intercept form that contains point (5, 6)?
y = negative one halfx + seventeen halves
y = 2x − 4
y = negative one halfx + seven halves
y = 2x + 16

y=2x-4

Step-by-step explanation:

step 1

Find the slope of the line QR

we have

x+2y=2

isolate the variable y

2y=-x+2

y=-(1/2)x+1

The slope m is equal to

m=-1/2

step 2

Find the slope of the line perpendicular to line QR

we know that

If two lines are perpendicular, then the product of their slopes is equal to -1

so

m1*m2=-1

we have

m1=-1/2

substitute

(-1/2)*m2=-1

m2=2

The slope of the line perpendicular to line QR is m=2

step 3

Find the equation of the line into slope intercept form

The equation of the line is equal to

y=mx+b

we have

m=2

point (5,6)

substitute and solve for b

6=(2)(5)+b

6=10+b

b=6-10

b=-4

The equation is equal to

y=2x-4

step-by-step explanation:

a and d